Question
Suppose a curve is traced by the parametric equations
x=1sin(t)
y=18-3cos^2(t)-4sin(t)
At what point (x,y) on this curve is the tangent line horizontal?
x=1sin(t)
y=18-3cos^2(t)-4sin(t)
At what point (x,y) on this curve is the tangent line horizontal?
Answers
When dy/dx = (dy/dt)/(dx/dt) = 0
Do the calculation and first find the value of t. Use that co calculate x and y
Do the calculation and first find the value of t. Use that co calculate x and y
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