Asked by Linda

State the domain and range of f(x) = 2sin(sort(3x-1)) + 3
Answered by Steve
as you know,
the domain of sin(x) is (-∞,∞)

The domain of √x x>=0
so, the domain of √(3x-1) is 3x-1 >= 0, or x >= 1/3

so, can you sort that out?