Let numerator be x and denominator be y
Fraction is x/y
1st case x+1/y+1 = 3/4
2nd case. X-3/y-4= 1/2
Solve for x and y
If one is added to both numenator ans denominator fraction become 3/4 however 3 is subtracted from both the fraction become 1/2.fnd the fraction.
3 answers
1st case (x+1)/(y+1)= 3/4
2nd case. (x-3)/(y-3)= 1/2 not y-4
2nd case. (x-3)/(y-3)= 1/2 not y-4
Well I have no idea how I got 4 there. I meant 3
1 answer