Asked by Kaelah
What is the ∆G for the following reaction under standard conditions (T = 298 K) for the formation of NH4NO3(s)?
2NH3(g) + 2O2(g) NH4NO3(s) + H2O(l)
Given:
NH4NO3(s): ∆Hf = -365.56 kJ ∆Sf = 151.08 J/K.
NH3(g): ∆Hf = -46.11 kJ ∆Sf = 192.45 J/K.
H2O(l): ∆Hf = -285.830 kJ ∆Sf = 69.91 J/K.
O2(g): ∆Hf = 0.00 kJ ∆Sf = 205 J/K.
2NH3(g) + 2O2(g) NH4NO3(s) + H2O(l)
Given:
NH4NO3(s): ∆Hf = -365.56 kJ ∆Sf = 151.08 J/K.
NH3(g): ∆Hf = -46.11 kJ ∆Sf = 192.45 J/K.
H2O(l): ∆Hf = -285.830 kJ ∆Sf = 69.91 J/K.
O2(g): ∆Hf = 0.00 kJ ∆Sf = 205 J/K.
Answers
Answered by
Mgomesi
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