Asked by richy
The value of Keq for the following reaction is 0.25:
SO2 (g) + NO2 (g)<~> SO3 (g) + NO (g)
The value of Keq at the same temperature for the reaction below is __________.
2SO2 (g) + 2NO2 (g)<~> 2SO3 (g) + 2NO (g)
answer is 0.25 how do i figure this out?
SO2 (g) + NO2 (g)<~> SO3 (g) + NO (g)
The value of Keq at the same temperature for the reaction below is __________.
2SO2 (g) + 2NO2 (g)<~> 2SO3 (g) + 2NO (g)
answer is 0.25 how do i figure this out?
Answers
Answered by
bobpursley
The rules for Keq are clear: the exponents used must be from the balanced equation, and we specify a standard for balancing as the lowest whole number ratio.
Balanced:
Ba + F2> BaF2
C+ 2H2 + 2O2 >> CO2 + 2H20
NOT C + H2+3/2 O2 >> CO2 + H2O
Balanced:
Ba + F2> BaF2
C+ 2H2 + 2O2 >> CO2 + 2H20
NOT C + H2+3/2 O2 >> CO2 + H2O
Answered by
Redeat
O.0625
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