Asked by JAYITA CHAUDHURI
A car moves at a speed of 40km/h, It is stopped by applying brakes which produces a uniformacceleration of -0.6m/s2. How much distance will the vehicle move before coming to stop?
Answers
Answered by
Henry
V^2 = Vo^2 + 2a*d.
Vo = 40km/h = 40,000m/3600s = 11.11 m/s.
V = 0, a = -0.6m/s^2, d = ?.
Vo = 40km/h = 40,000m/3600s = 11.11 m/s.
V = 0, a = -0.6m/s^2, d = ?.
Answered by
bobpursley
d= -vo^2/2a
Answered by
Anonymous
A car moves at a speed of 40 km/h. It is stopped by applying brake which produces a uniform acceleration of -0.5 m/ s². How much distance will the vehicle move before coming to stop?
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