Asked by Victoria

An electron with a speed of 0.988c is emitted by a supernova, where c is the speed of light. What is the magnitude of the momentum of this electron?

Thanks for any help you can offer! I've tried so many things!
Answered by Steve
it's mv/√(1 - v^2/c^2)

see

http://hyperphysics.phy-astr.gsu.edu/hbase/relativ/relmom.html
Answered by Scott
the momentum is the product (multiply) of the relativistic mass and the velocity

the relativistic mass is the rest mass multiplied by gamma (the relativistic "fudge factor")

gamma = 1 / sqrt[1 - (v² / c²)]

p = gamma * rest mass * v


hyperphysics (web) is a good reference
Answered by Victoria
So this is how I calculated, but can speed be taken for the velocity?
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