Asked by Victoria
An electron with a speed of 0.988c is emitted by a supernova, where c is the speed of light. What is the magnitude of the momentum of this electron?
Thanks for any help you can offer! I've tried so many things!
Thanks for any help you can offer! I've tried so many things!
Answers
Answered by
Steve
it's mv/√(1 - v^2/c^2)
see
http://hyperphysics.phy-astr.gsu.edu/hbase/relativ/relmom.html
see
http://hyperphysics.phy-astr.gsu.edu/hbase/relativ/relmom.html
Answered by
Scott
the momentum is the product (multiply) of the relativistic mass and the velocity
the relativistic mass is the rest mass multiplied by gamma (the relativistic "fudge factor")
gamma = 1 / sqrt[1 - (v² / c²)]
p = gamma * rest mass * v
hyperphysics (web) is a good reference
the relativistic mass is the rest mass multiplied by gamma (the relativistic "fudge factor")
gamma = 1 / sqrt[1 - (v² / c²)]
p = gamma * rest mass * v
hyperphysics (web) is a good reference
Answered by
Victoria
So this is how I calculated, but can speed be taken for the velocity?
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