Asked by Anonymous
If b= 11a, what is the average (arithmetic mean) of b and a in terms of a?
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Answered by
Anonymous
average = ( a + b ) / 2
substitute the value of b = 11a
( a + b ) / 2
( a + 11a ) / 2
= 12a / 2
= 6a
substitute the value of b = 11a
( a + b ) / 2
( a + 11a ) / 2
= 12a / 2
= 6a
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