Asked by Ed
Solve the following equation on the interval [0,2pi) if sin = -0.29?
Answers
Answered by
Steve
you know that sin(x) is negative in QIII and QIV
sin(.294) = 0.29
so, you want the numbers
π+.294 and 2π-.294
sin(.294) = 0.29
so, you want the numbers
π+.294 and 2π-.294
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