Asked by Meiza
Find the standard and general equation of a parabola with a vertex at (0,0) and graph passing through (3,5) Axis of Symmetry at x-axis.
Answers
Answered by
Reiny
Since you know the vertex, your equation must be
x = a(y-0)^2 + 0 , if the axis of symmetry is horizontal
x = ay^2
but (3,5) lies on it, so
3 = a(25)
a = 3/25
x = (3/25)y^2
or
25x = 3y^2
x = a(y-0)^2 + 0 , if the axis of symmetry is horizontal
x = ay^2
but (3,5) lies on it, so
3 = a(25)
a = 3/25
x = (3/25)y^2
or
25x = 3y^2