Asked by kent
a person in a hot air balloon ascending vertically at a constant rate of 12mm/s drops a rock over the side when the balloon is 40m above the ground how long will it take the rock to reach the ground
Answers
Answered by
Anonymous
12 mm/s = .012 m/s = Vi initial speed up
h = Hi + Vi t - 4.9 t^2
0 = 40 + .012 t - 4.9 t^2
Solve quadratic for t
h = Hi + Vi t - 4.9 t^2
0 = 40 + .012 t - 4.9 t^2
Solve quadratic for t
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