Asked by gary
a person in a hot air balloon ascending vertically at a constant rate of 12m/s drops a rock over the side when the balloon is 40 m above the ground, what is the velocity of the rock just before it hits the ground, and how long will it take the rock to reach the ground
Answers
Answered by
Scott
the rock reaches its peak after 12/g s
it ascends at an average rate of
... (12 m/s + 0 m/s) / 2
it then free falls from h
m g h = ½ m v² ... v = √(2 g h)
t = 2 h / v
it ascends at an average rate of
... (12 m/s + 0 m/s) / 2
it then free falls from h
m g h = ½ m v² ... v = √(2 g h)
t = 2 h / v
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