Question
The second and sixth terms of an arithmetic sequence is 2:5 and their sum is 28. Find the sum of the first 10th term.
Answers
Steve
(a+d)/(a+5d) = 2/5
a+d + a+5d = 28
find a and d, and then
S10 = 10/2 (2a+9d)
a+d + a+5d = 28
find a and d, and then
S10 = 10/2 (2a+9d)