Asked by Kennedy
The third and sixth terms of a geometric sequence are -75 and -9375 respectively. Find the first term, the common ratio, and an explicit rule for the nth term.
Answers
Answered by
Reiny
t3 = ar^2 = -75
t6 = ar^5 = -9375
divide them
r^3 = 125
r = 5
in ar^2 = -75
a(25) = -75
a = -3
term(n) = -3(5)^(n-1)
t6 = ar^5 = -9375
divide them
r^3 = 125
r = 5
in ar^2 = -75
a(25) = -75
a = -3
term(n) = -3(5)^(n-1)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.