Asked by anonymous
A 50 kg pole vaulter has a horizontal velocity of 8 m/s at the completion of her approach run, and her center of gravity is 1.0 m high. Estimate how high she should be able to vault if her kinetic and potential energies were all converted to potential energy.
Answers
Answered by
Damon
ke = (1/2) m v^2
pe = m g h where h is height above one meter
(1/2) m v^2 = m (9.8) h
v^2 = 2 (9.8) h
h = 64/19.6
total height = 64/19.6 + 1
pe = m g h where h is height above one meter
(1/2) m v^2 = m (9.8) h
v^2 = 2 (9.8) h
h = 64/19.6
total height = 64/19.6 + 1
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