a Particle in x-y plane with const acceleration of 1.5m/s sq. in the direction making an angle 37degree with x_axis.

Question

At t=0 the particle is at origin and its velocity is 8m/s along x axis.Find the velocity and the position of the particle at t=4sec.

Answer 1

V = 8 + 1.5[37o]*4 = 8 + 6[37o] = 8 + 6*Cos37+6*sin37 = 8 + 4.79+3.61i = 12.79 + 3.61i = 13.3m/s[15.8o]