Question
a driver starting from rest accelerates at a rate of 1.5m/s^2 for 20s until reaching a certain speed she then continues driving at this constant speed for an additional 20s what maximum speed does the driver attain what total distance does the driver cover during the 40s that she is in motion
Answers
bobpursley
max speed:
v=at=1.5*20=30m/s
distance covered during acceleration:
d=1/2 a t^2=1/2*1.5*400=300m
constant speed: distance covered
d=30m/s*20s=600m
total distance=300+600=900m
v=at=1.5*20=30m/s
distance covered during acceleration:
d=1/2 a t^2=1/2*1.5*400=300m
constant speed: distance covered
d=30m/s*20s=600m
total distance=300+600=900m