a driver starting from rest accelerates at a rate of 1.5m/s^2 for 20s until reaching a certain speed she then continues driving at this constant speed for an additional 20s what maximum speed does the driver attain what total distance does the driver cover during the 40s that she is in motion

Answer 1

max speed:
v=at=1.5*20=30m/s
distance covered during acceleration:
d=1/2 a t^2=1/2*1.5*400=300m

constant speed: distance covered
d=30m/s*20s=600m

total distance=300+600=900m