Asked by Motombo
                An open box , no more than 5 cm in height, is to be formed by cutting four identical squares from the corners of a sheet metal 25 cm by 32 cm, and folding up the metal to form sides.The capacity of the box must be 1575 (cm squared). What is the side length of the squares removed? 
            
            
        Answers
                    Answered by
            Scott
            
    x (25 - 2x) (32 - 2x) = 1575
expand the cubic equation
find a solver online (use google)
    
expand the cubic equation
find a solver online (use google)
                    Answered by
            Reiny
            
    size of side of square to be cut out --- x cm
volume = (25-2x)(32-2x)(x)
= 1575
expanding we get:
4x^3-114x^2 + 800x = 1575
4x^3 - 114x^2 + 800x - 1575 = 0
messy to solve, gave up trying to factor, and used Wolfram:
http://www.wolframalpha.com/input/?i=solve+4x%5E3+-+114x%5E2+%2B+800x+-+1575+%3D+0
got x = 3.5 or x = numbers outside the domain of 0 < x < 5
the size of squares to be removed is 3.5 cm by 3.5 cm
check:
3.5(25-7)(32-7)
= 1575
    
volume = (25-2x)(32-2x)(x)
= 1575
expanding we get:
4x^3-114x^2 + 800x = 1575
4x^3 - 114x^2 + 800x - 1575 = 0
messy to solve, gave up trying to factor, and used Wolfram:
http://www.wolframalpha.com/input/?i=solve+4x%5E3+-+114x%5E2+%2B+800x+-+1575+%3D+0
got x = 3.5 or x = numbers outside the domain of 0 < x < 5
the size of squares to be removed is 3.5 cm by 3.5 cm
check:
3.5(25-7)(32-7)
= 1575
                    Answered by
            Motombo
            
    Thank you
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.