Asked by Joel
If X=loga(n), y=logc(n) where nis not equal to one . Prove that x-y/x+y=logb(c)-logb(a)/logb(c)+logb(a)
Answers
Answered by
Steve
1/x = logn(a)
1/y = logn(c)
(x-y)/(x+y) = (1/y - 1/x)/(1/y + 1/x)
= logn(c/a)/logn(c*a)
logb(c)-logb(a) = logb(c/a)
logb(c)+logb(a) = logb(c*a)
The two ratios are equal.
1/y = logn(c)
(x-y)/(x+y) = (1/y - 1/x)/(1/y + 1/x)
= logn(c/a)/logn(c*a)
logb(c)-logb(a) = logb(c/a)
logb(c)+logb(a) = logb(c*a)
The two ratios are equal.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.