Asked by Nikki
I am asked to write a logarithmic expresion as a single logarithm with coefficient 1 and simplify as much as possible. The equation is:
4logbase5Y-3logbase5X+1/2logbase5Z.
Could some please help me I am not understanding this whole Logarithm thing.
4logbase5Y-3logbase5X+1/2logbase5Z.
Could some please help me I am not understanding this whole Logarithm thing.
Answers
Answered by
Steve
first of all, it's just an expression, not an equation (no = sign)
Since loga + logb = log(a*b)
just a x^a * a^b = x^(a+b)
log x^n = log(x*x*x*x...)= n*logx
assuming logs base 5, but the base does not matter if all the logs are to the same base; the rules apply regardless of the base
4logx-3logy + 1/2 logz
= log(x^4√z/y^3)
Since loga + logb = log(a*b)
just a x^a * a^b = x^(a+b)
log x^n = log(x*x*x*x...)= n*logx
assuming logs base 5, but the base does not matter if all the logs are to the same base; the rules apply regardless of the base
4logx-3logy + 1/2 logz
= log(x^4√z/y^3)
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