Asked by DANIELLE
SIMPLIFY THE FOLLOWING EXPRESSION: Z=LOG(E^5Y)
i MOVED THE EXPONENT TO THE FRONT:
Z=5YLOGE IS THIS CORRECT?
i MOVED THE EXPONENT TO THE FRONT:
Z=5YLOGE IS THIS CORRECT?
Answers
Answered by
Steve
yes, as far as you went.
But, if you are using natural logs, log(e) = 1, so the answer is just 5y
By definition
log<sub>b</sub>b^n = n
b^(log<sub>b</sub>n) = n
because logs and powers are inverse functions, just like √x and x^2 are inverses.
Like + and - or * and /
It's just that we don't have any special symbols for the notation.
But, if you are using natural logs, log(e) = 1, so the answer is just 5y
By definition
log<sub>b</sub>b^n = n
b^(log<sub>b</sub>n) = n
because logs and powers are inverse functions, just like √x and x^2 are inverses.
Like + and - or * and /
It's just that we don't have any special symbols for the notation.
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