Asked by Yash
An aeroplane takes off from runway making an angle of 30 horizontally at a speed 500ms find the height attained by the aeroplane after 15s?
Answers
Answered by
Steve
h/(500*15) = 1/2
Review the properties of a 30-60-90 right triangle.
Review the properties of a 30-60-90 right triangle.
Answered by
rogba
200
Answered by
Kausik Kar
Vertical velocity (component) of the plane= 500sin30° m/s= 250 m/s.
H= ut (REMEMBER! IT IS NOT A PROJECTILE! IT IS A PLANE AND IT WILL MOST PROBABLY RISE WITH THE SAME SPEED IN THIS SCENARIO!).
H= ut
H= 250*15
H= 3750m. (Height attained by it after 15s).
H= ut (REMEMBER! IT IS NOT A PROJECTILE! IT IS A PLANE AND IT WILL MOST PROBABLY RISE WITH THE SAME SPEED IN THIS SCENARIO!).
H= ut
H= 250*15
H= 3750m. (Height attained by it after 15s).
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