Asked by Anonymous
When the equation below is balanced and all coefficients are in the lowest, whole number ratio, the coefficients are:
C2H6 + O2 ¨ CO2 + H2O
I am currently doing an online worksheet to improve in chemistry and I am not quite understanding how to find the coefficients and how to solve problems like these. Any help would be greatly appreciated. Thanks.
C2H6 + O2 ¨ CO2 + H2O
I am currently doing an online worksheet to improve in chemistry and I am not quite understanding how to find the coefficients and how to solve problems like these. Any help would be greatly appreciated. Thanks.
Answers
Answered by
Steve
C2 yields 2CO2
H6 yields 3H2O
but that leaves us with 7O, and O only comes in O2 molecules. So, double everything to get
2C2H6 + 7O2 = 4CO2 + 6H2O
on the left: 4C 12H 14O
on the right: 4C 12H 14O
it balances
H6 yields 3H2O
but that leaves us with 7O, and O only comes in O2 molecules. So, double everything to get
2C2H6 + 7O2 = 4CO2 + 6H2O
on the left: 4C 12H 14O
on the right: 4C 12H 14O
it balances
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