Asked by Mariah
Given the balanced neutralization equation: H2SO4+2KOH→K2SO4+2H2O
How many moles of potassium hydroxide (KOH) are required to neutralize 4.5 mol of sulfuric acid (H2SO4)? Assume that the sulfuric acid completely dissociates in water.
2 mols of KOH = 1 mol of H2SO2
4.5 mols of H2SO4 = 9 mols of KOH
How many moles of potassium hydroxide (KOH) are required to neutralize 4.5 mol of sulfuric acid (H2SO4)? Assume that the sulfuric acid completely dissociates in water.
2 mols of KOH = 1 mol of H2SO2
4.5 mols of H2SO4 = 9 mols of KOH
Answers
Answered by
DrBob222
right. Go the head of the class.
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