Asked by Momen
the plane of a circle of center M contained in plane X , MA perpendicular to plane X and if AM = 2√7 cm , BC = 8 cm find the length of AB.. where BC is a tangent and AMB is right at M .... find the length of AB ..?
Answers
Answered by
Steve
BC is a tangent to what?
I see line MA sticking up out of the plane X and B in the plane, but where is C?
I see line MA sticking up out of the plane X and B in the plane, but where is C?
Answered by
Momen
C is the point of the tangent to the circle
Answered by
Steve
oh, right. I forgot about the circle.
Hmmm. Still seems a bit murky. I see that if the radius of the circle is r,
r^2+8^2 = MB^2
MB^2+MA^2 = AB^2
so,
AB^2 = r^2+64+28 = r^2+92
But I can't figure out how to pin down r. Maybe you can take it from here.
Hmmm. Still seems a bit murky. I see that if the radius of the circle is r,
r^2+8^2 = MB^2
MB^2+MA^2 = AB^2
so,
AB^2 = r^2+64+28 = r^2+92
But I can't figure out how to pin down r. Maybe you can take it from here.
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