Question

Brenda’s Bike Booth, at the mall, allows people to order a bike in their choice of 4 colors (Atomic Tangerine, Banana, Café Noir, or Dollar Bill) and the options of with or without a basket; with or without a horn. Given all of these options, what’s the probability that my daughter chooses either a banana colored bike with a basket, or an Atomic Tangerine colored bike without a horn?

*First part is the fundamental counting principle I believe = 16. But I am lost figuring out the probability! Thanks

Answer 1

The first part you have right fundamental counting principal = 4*2*2 = 16
Next we need to find out what are the chances she picks the banana colored bike with a basket = 2/16 or 1/8
and the chance she picks the Atomic Tangerine bike without the horn = 2/16 or 1/8
The key word in this question is OR. Chances of picking one bike OR the other. the formula of finding the probability of or = Probability(A)+P(B)-P(A&B)
Before we can do that we must find the Probability of (A&B)= 1/8*1/8=1/64
Now we can find the probability of OR = 1/8+1/8-1/64 = 15/64 or 0.234 which = 23.4%