Asked by maiah
I can't solve this one:
The second term of an arithmetic sequence is 24 and the fifth term is 3.Find the first term and the common difference.
How could I get the answers if there's only two given numbers?
The second term of an arithmetic sequence is 24 and the fifth term is 3.Find the first term and the common difference.
How could I get the answers if there's only two given numbers?
Answers
Answered by
Josh
2nd term = 24
5th term = 3
24-3 = 21
5-2 = 3
21/3 = 7
common difference = -7 since the terms are decreasing
so to find the first term, subtract -7 from 24
so the first term is equal to 31
5th term = 3
24-3 = 21
5-2 = 3
21/3 = 7
common difference = -7 since the terms are decreasing
so to find the first term, subtract -7 from 24
so the first term is equal to 31
Answered by
Reiny
traditional method:
a+d = 24
a+4d = 3
subtract them:
3d = -21
d = -7
sub into a+d = 24
a - 7 = 24
a = 31
first term is 31, commond difference is -7
a+d = 24
a+4d = 3
subtract them:
3d = -21
d = -7
sub into a+d = 24
a - 7 = 24
a = 31
first term is 31, commond difference is -7
Answered by
Anonymous
how many terms are there in an arithmetic sequence those first term is -4 common difference 2 and last term is 24?
Answered by
Jovelyn
The second term if can arithmetic sequence is 24 and the fifth term is 3 find the first term and common difference
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