Asked by liliy
A cash register contains $5 bills and $10 bills with a total value of $350. If there are 46 bills total, then how many of each does the register contain?
answer is 22
answer is 22
Answers
Answered by
Ms. Sue
No.
5x + 10y = 350
x + y = 46
5x + 10y = 350
x + y = 46
Answered by
liliy
I have the same equation you have figure out.
i figure out the problem i receive this answer 22
i figure out the problem i receive this answer 22
Answered by
Ms. Sue
x = 5 dollar bills
y = 10 dollar bills
5x + 10y = 350
x + y = 46
x = 46 - y
5(46-y) + 10y = 350
230 - 5y + 10y = 350
5y = 120
y = 24
There are 24 ten-dollar bills and 22 five-dollar bills.
y = 10 dollar bills
5x + 10y = 350
x + y = 46
x = 46 - y
5(46-y) + 10y = 350
230 - 5y + 10y = 350
5y = 120
y = 24
There are 24 ten-dollar bills and 22 five-dollar bills.
Answered by
lin
24 tens and 22 five
Answered by
Timothy has $350 in $10 and $20 bills in his cash drawer. If the number of $10 bills is three times
Timothy has $350 in $10 and $20 bills in his cash drawer. If the number of $10 bills is three times the number of $20 bills, how many of each are in the drawer?
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