F-25=T
5*F+10*T=560
5F+10*(F-25)=560
15F=560+250
F=810/15=54
T=29
5*F+10*T=560
5F+10*(F-25)=560
15F=560+250
F=810/15=54
T=29
Let's assume the number of ten dollar bills is x.
Since there are 25 more five dollar bills than ten dollar bills, the number of five dollar bills would be (x + 25).
Now, we can set up two equations:
Equation 1: 10x + 5(x + 25) = 560 (to represent the total amount of money in the cash register)
Equation 2: (x + 25) = x + 25 (to represent the relationship between the number of five dollar bills and ten dollar bills)
Now, let's solve the equations to find the values of x and (x + 25):
Expanding Equation 1:
10x + 5x + 125 = 560
Combining like terms:
15x + 125 = 560
Subtracting 125 from both sides of the equation:
15x = 435
Dividing both sides by 15:
x = 29
Substituting the value of x back into Equation 2:
(x + 25) = 29 + 25
(x + 25) = 54
Therefore, there are 29 ten dollar bills and 54 five dollar bills in the cash register.