Asked by tomi
What electron transition in a hydrogen atom, starting from the orbit 10, will produce infrared light of wavelength 3040 ?
Answers
Answered by
drwls
What are the wavelength units? micrometers? nanometers? inches? Just giving a number isnt enough.
Once you have figured that out, use the appropriate Rydberg formula with an upper level quantum number of n = 10 and solve for the lower level.
Once you have figured that out, use the appropriate Rydberg formula with an upper level quantum number of n = 10 and solve for the lower level.
Answered by
Damon
3040 what? nanometers ?
use Rydberg equation
3040 *10^-9 m * 10^2 cm/m = 3040*10^-7 cm
1/wavelength = 3.29*10^3
1/wavelength in cm =109,678cm^-1 = (1/n1^2 - 1/n2^2)
3.29 *10^3 = 1.1*10^5 (1/n1^2 -1/n2^2)
here n2 = 10
2.99 *10^-2 = (1/n1^2 -.01)
.0299 +.01 = 1/n1^2
.04 = 1/n1^2
n1^2 = 100/4
n1 = 10/2 = 5
so level 10 down to level 5
use Rydberg equation
3040 *10^-9 m * 10^2 cm/m = 3040*10^-7 cm
1/wavelength = 3.29*10^3
1/wavelength in cm =109,678cm^-1 = (1/n1^2 - 1/n2^2)
3.29 *10^3 = 1.1*10^5 (1/n1^2 -1/n2^2)
here n2 = 10
2.99 *10^-2 = (1/n1^2 -.01)
.0299 +.01 = 1/n1^2
.04 = 1/n1^2
n1^2 = 100/4
n1 = 10/2 = 5
so level 10 down to level 5
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