Question
The table below shows a frequency distribution of the number of pickup trucks sold at 85 truck dealerships in Maine over an 18-month period.
Number of trucks sold/Number of dealerships:
70-90/2
90-110/11
110-130/39
130-150/17
150-170/9
170-190/7
Find the interval about the sample mean such that the probability is 0.90 that the true mean lies within the interval. (When P=90%, t=1.65)
I know that N=85, but I do not know how to find the standard deviation or mean in order to work the rest of the problem. Any help would be great.
Number of trucks sold/Number of dealerships:
70-90/2
90-110/11
110-130/39
130-150/17
150-170/9
170-190/7
Find the interval about the sample mean such that the probability is 0.90 that the true mean lies within the interval. (When P=90%, t=1.65)
I know that N=85, but I do not know how to find the standard deviation or mean in order to work the rest of the problem. Any help would be great.
Answers
SMALL-SAMPLE CONFIDENCE INTERVAL FOR A POPLATION MEAN
90% Confidence Interval = x-bar +/- 1.65 * s/SQRT(n)
n = NUMBER OF SAMPLES [3]
Cumulative Distribution Function
Student's t distribution with 3 DF
x P( X <= x )
1.65 0.901247
90% Confidence Interval = x-bar +/- 1.65 * s/SQRT(n)
n = NUMBER OF SAMPLES [3]
Cumulative Distribution Function
Student's t distribution with 3 DF
x P( X <= x )
1.65 0.901247
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