Question
How much energy, in joules, must be absorbed to convert to Na all the atoms present in 1.00mg of gaseous Na? The first ionization energy of Na is 495.8kj/mol .
Answers
Damon
Assume you mean to Na+
Na is 23 grams/mole
so we have 10^-3 grams (1 mole/23 grams) = .0435 *10^-3 moles
.0435 * 10^-3 * 495.8 *10^3 J/mole = 21.6 Joules
Na is 23 grams/mole
so we have 10^-3 grams (1 mole/23 grams) = .0435 *10^-3 moles
.0435 * 10^-3 * 495.8 *10^3 J/mole = 21.6 Joules