Asked by tomi
How much energy, in joules, must be absorbed to convert to Na all the atoms present in 1.00mg of gaseous Na? The first ionization energy of Na is 495.8kj/mol .
Answers
Answered by
Damon
Assume you mean to Na+
Na is 23 grams/mole
so we have 10^-3 grams (1 mole/23 grams) = .0435 *10^-3 moles
.0435 * 10^-3 * 495.8 *10^3 J/mole = 21.6 Joules
Na is 23 grams/mole
so we have 10^-3 grams (1 mole/23 grams) = .0435 *10^-3 moles
.0435 * 10^-3 * 495.8 *10^3 J/mole = 21.6 Joules
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