Asked by Harsh
An object is moving with uniform acceleration and it's velocity after 5 second is 25m/s after 8 second it is 34m/s find distance travelled by object in 12 second
Answers
Answered by
bobpursley
v(t)=vo+at
25=vo+5a
34=vo+8a
subtract 1 from 2
9=3a
a=3m/s^
25=vo+15
vo=10m/s
v(12)=10+3*12= 46m/s
avg velocity=(10+46)/2=28m/s
distance=28m/s*12sec...
25=vo+5a
34=vo+8a
subtract 1 from 2
9=3a
a=3m/s^
25=vo+15
vo=10m/s
v(12)=10+3*12= 46m/s
avg velocity=(10+46)/2=28m/s
distance=28m/s*12sec...