Asked by Jenny
Ella wants to build a rectangular pen for her dogs with two distinct sections. The area of the enclosure can be represented by A= Xy and the total length of fencing can be represented by 3x + 2y = 60. If she had 60 ft of fencing to work with, determine the maximum area she can enclose.
Answers
Answered by
bobpursley
Wondering if in area, the X is the same thing as x in the perimeter.
Area=xy=x(30-3x/2)
Assuming you know some calculus first:
dArea/dx=0=(30-3x/2)+x(-3/2)
3x=60-3x
x=10, then y=15 for max.
Now if you are not a calculus girl,
A=x(30-3x/2)= which has zeroes at x=0, and x=20
Now this is a parabola, so the max must be halfway between the zeroes, or x=10 at the peak. Then y=15
Area=xy=x(30-3x/2)
Assuming you know some calculus first:
dArea/dx=0=(30-3x/2)+x(-3/2)
3x=60-3x
x=10, then y=15 for max.
Now if you are not a calculus girl,
A=x(30-3x/2)= which has zeroes at x=0, and x=20
Now this is a parabola, so the max must be halfway between the zeroes, or x=10 at the peak. Then y=15
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.