Asked by donna
How would you prepare 3.5 L of a 0.9M solution of KCl?
A. Add 23 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark.
B. Add 233 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark.
C. Add 287 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark.
D. Add 567 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark.
A. Add 23 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark.
B. Add 233 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark.
C. Add 287 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark.
D. Add 567 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark.
Answers
Answered by
bobpursley
mass=Molarity*molemas*volume
= .9*74.5*3.5= you do it.
Then add water to the 3.5Liter mark, stir, and label.
= .9*74.5*3.5= you do it.
Then add water to the 3.5Liter mark, stir, and label.
There are no AI answers yet. The ability to request AI answers is coming soon!