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Question

50.00mL of 0.250M hydrochloric acid was added to 25.00mL of 0.300M potassium hydroxide.
Calculate the pH of the resulting solution.
9 years ago

Answers

Scott
12.5 mM HCl and 7.5 mM KOH

after netralization ... 5.0 mM HCl in
75.0 mL of solution ... .067 M HCl

pH = -log[H⁺] = -log[.067]
9 years ago

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