Asked by Tommy

50.00mL of 0.250M hydrochloric acid was added to 25.00mL of 0.300M potassium hydroxide.
Calculate the pH of the resulting solution.

Answers

Answered by Scott
12.5 mM HCl and 7.5 mM KOH

after netralization ... 5.0 mM HCl in
75.0 mL of solution ... .067 M HCl

pH = -log[H⁺] = -log[.067]
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