Asked by deanna
                5. Come up with a new linear function that has a slope that falls in the range −1 < m < 0 . Choose two different initial values. For this new linear function,
what happens to the function’s values after many iterations? Are the
function’s values getting close to a particular number in each case?
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the function for the two questions below is:
g(x) =− 2 −x 2+ 4
7. What is the loop that forms after many iterations when the initial value of g is 1.7?
8. What is the loop that forms after many iterations when the initial value of g is 1.72?
            
            
        what happens to the function’s values after many iterations? Are the
function’s values getting close to a particular number in each case?
-----------------------------------
the function for the two questions below is:
g(x) =− 2 −x 2+ 4
7. What is the loop that forms after many iterations when the initial value of g is 1.7?
8. What is the loop that forms after many iterations when the initial value of g is 1.72?
Answers
                    Answered by
            Steve
            
    I suspect a typo
g(x) =− 2 −x 2+ 4
is the same as
-2 - x^2 + 4 = 2-x^2
Clean it up and show how far you got.
    
g(x) =− 2 −x 2+ 4
is the same as
-2 - x^2 + 4 = 2-x^2
Clean it up and show how far you got.
                    Answered by
            deanna
            
    i meant to put g(x) = -2 lx-2l + 4
    
                    Answered by
            Hailey
            
    Did you ever get it? I'm stuck too
    
                    Answered by
            shaniqua
            
    ???????????? im stuck
    
                    Answered by
            Anonymous
            
    Still stuck 
    
                    Answered by
            T-REX
            
    I'm a human boy. Shhh. Don't think anything of the name...
    
                    Answered by
            mykos
            
    I got the first one but not the second. Either I'm doing it wrong or the second one doesn't loop. 
    
                    Answered by
            anon
            
    this portfolio is trash who agrees
    
                    Answered by
            maybe she snapped
            
    agreed
    
                    Answered by
            maybe she snapped
            
    not even in this class and it looks like a whole mess
    
                    Answered by
            CulturalSinger
            
    oh come on people we need help. so your telling me there is no one here to help us
    
                    Answered by
            CulturalSinger
            
    i also agree with you anon
    
                    Answered by
            otaku
            
    7.  The loop that forms after many iterations is 1.6 and 3.2
8. This loop is never ending it took me 13 iterations to see that it will works it will result in 2.24 again just as the 3 iteration.
    
8. This loop is never ending it took me 13 iterations to see that it will works it will result in 2.24 again just as the 3 iteration.
                    Answered by
            anonymous
            
    answer: The value of the function decreases and the values are not getting close to a particular number since they will be decreasing indefinitely
    
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