Asked by deanna

5. Come up with a new linear function that has a slope that falls in the range −1 < m < 0 . Choose two different initial values. For this new linear function,
what happens to the function’s values after many iterations? Are the
function’s values getting close to a particular number in each case?
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the function for the two questions below is:
g(x) =− 2 −x 2+ 4


7. What is the loop that forms after many iterations when the initial value of g is 1.7?

8. What is the loop that forms after many iterations when the initial value of g is 1.72?




Answered by Steve
I suspect a typo

g(x) =− 2 −x 2+ 4
is the same as

-2 - x^2 + 4 = 2-x^2

Clean it up and show how far you got.
Answered by deanna
i meant to put g(x) = -2 lx-2l + 4
Answered by Hailey
Did you ever get it? I'm stuck too
Answered by shaniqua
???????????? im stuck
Answered by Anonymous
Still stuck
Answered by T-REX
I'm a human boy. Shhh. Don't think anything of the name...
Answered by mykos
I got the first one but not the second. Either I'm doing it wrong or the second one doesn't loop.
Answered by anon
this portfolio is trash who agrees
Answered by maybe she snapped
agreed
Answered by maybe she snapped
not even in this class and it looks like a whole mess
Answered by CulturalSinger
oh come on people we need help. so your telling me there is no one here to help us
Answered by CulturalSinger
i also agree with you anon
Answered by otaku
7. The loop that forms after many iterations is 1.6 and 3.2
8. This loop is never ending it took me 13 iterations to see that it will works it will result in 2.24 again just as the 3 iteration.
Answered by anonymous
answer: The value of the function decreases and the values are not getting close to a particular number since they will be decreasing indefinitely