Asked by Mary
How do I solve: sin theta = -1 for all real values of theta?
Answers
Answered by
Damon
sin theta = -1 for 3 pi/2 and every full circle (2 pi) after that
so
theta = 3 pi/2 + 2 pi n
for n = 0 to oo
so
theta = 3 pi/2 + 2 pi n
for n = 0 to oo
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