Asked by mitch
A toy rocket is launched straight up into the air with an initial velocity of 60 ft/s from a table 3 ft above the ground. If acceleration due to gravity is –16 ft/s2, approximately how many seconds after the launch will the toy rocket reach the ground?
Answers
Answered by
Reiny
h = -16t^2 + 60t + 3
at ground level , h = 0
16t^2 - 60t - 3 = 0
t = (60 ± √3792)/32
t = 3.799.. or t = a negative
it will take appr 3.8 seconds to hit the ground
at ground level , h = 0
16t^2 - 60t - 3 = 0
t = (60 ± √3792)/32
t = 3.799.. or t = a negative
it will take appr 3.8 seconds to hit the ground
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