Question
Calculate the mass of 3.20 mol of sodium hydroxide, NaOH.
M(NaOH) = 40.0g mol-1
Would the following be the correct workings?
n= 3.20 mol M=40.0g mol-1
m(NaOH) = n x M
= 3.20 mol x 40.0g mol-1
= 128 g NaOH
Is this the correct workings?
M(NaOH) = 40.0g mol-1
Would the following be the correct workings?
n= 3.20 mol M=40.0g mol-1
m(NaOH) = n x M
= 3.20 mol x 40.0g mol-1
= 128 g NaOH
Is this the correct workings?