142 out of 507 people were right. Calculate a 95% confidence interval for the proportion of the entire population that could be right. I did some of the work and got .72...don't know what to do with this? Please help.

Answer 1

p = 142/ 507 = 0.28

SD = sqrt(p(1-p)/n)

0.28-+ 0.039

(.241, .319)

Answer 2

so I could say that with 95% confidence, between 24.1% and 31.9% of the entire population could be right?

Answer 3

you know I am getting .0199 SD =srt(.28(1-.28)/506 = .0119? Please check for me again?

Answer 4

YES. IF YOUR PROFESSOR SAID THAT YOUR ANSWER SHOULD BE IN PERCENT.

P = 142/507 = 0.28

SD = SQRT( .28*.72/507)

SQRT(0.2016/507) = 0.0199

Z = 1.96

0.28-+1.96*0.0199

0.28-+ 0.039
( 0.241, 0.319)

Answer 5

I get it now...I was missing a step too! Thanks Much!