A truck accelerates from rest at a constant rate of 2 m/s2. How far does the truck travel in the first 3.00 s?

d = 1/2 a t²

To find the distance traveled by the truck in the first 3.00 seconds, we can use the formula:

distance = initial velocity * time + (1/2) * acceleration * time^2

Given:
Initial velocity (rest) = 0 m/s
Acceleration = 2 m/s^2
Time = 3.00 s

Plugging in the values into the formula:

distance = 0 * 3 + (1/2) * 2 * 3^2
distance = 0 + (1/2) * 2 * 9
distance = 0 + 1 * 9
distance = 9 meters

Therefore, the truck travels 9.0 meters in the first 3.00 seconds. The answer is option C.

To find the distance traveled by the truck in the first 3.00 seconds, we can use the kinematic equation:

distance = initial velocity * time + 0.5 * acceleration * time^2

In this case, the truck starts from rest (initial velocity = 0 m/s) and accelerates at a constant rate of 2 m/s^2 for 3.00 seconds.

Plugging those values into the equation:

distance = 0 * 3.00 + 0.5 * 2 * (3.00)^2

Calculating further:

distance = 0 + 0.5 * 2 * 9.00

distance = 0 + 1 * 9.00

distance = 9.00 meters

Therefore, the truck would travel a distance of 9.00 meters in the first 3.00 seconds.

Thus, the correct option is C. 9.0 m.