Asked by Giovanni

Convert the given polar equation to a Cartesian equation.

r^2=4sec(theta)csc(theta)
Answered by Reiny
secØ = r/x , cscØ = r/y

so r^2 = 4(r/x)(r/y)
r^2 = 4r^2/(xy)
1 = 4/(xy)

xy = 4