Asked by Giovanni
Convert the given polar equation to a Cartesian equation.
r^2=4sec(theta)csc(theta)
r^2=4sec(theta)csc(theta)
Answers
Answered by
Reiny
secØ = r/x , cscØ = r/y
so r^2 = 4(r/x)(r/y)
r^2 = 4r^2/(xy)
1 = 4/(xy)
xy = 4
so r^2 = 4(r/x)(r/y)
r^2 = 4r^2/(xy)
1 = 4/(xy)
xy = 4
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