Question

Convert 2x^2-2y^2=8y to polar form. Express as the equation r(theta).

Answer 1

ditch the factor of 2, and you have
r^2 cos^2θ - r^2 sin^2θ = 8 r sinθ
r^2 cos(2θ) = 8r sinθ
r cos(2θ) = 8 sinθ
r = 8sinθ/cos(2θ)

Answer 2

rats. Change all those 8's to 4's.