Asked by Anonymous
Two house A and B are 100m apart and B is due east of A. The bearing of a church c from A is 145 and from B is 225, which house is nearer to the church and by how much
Answers
Answered by
bobpursley
draw the triangle, label the sides, and angles.
Angle A is 55deg
Angle B is 45 deg
Angle C is 80 deg
(the ABC co-inside with the ABC above)sides a and b are opposite the angles A and B
law of sines:
100m/SinC=b/SinB solve for b
and
100m/SinC=a/SinA solve for a
Angle A is 55deg
Angle B is 45 deg
Angle C is 80 deg
(the ABC co-inside with the ABC above)sides a and b are opposite the angles A and B
law of sines:
100m/SinC=b/SinB solve for b
and
100m/SinC=a/SinA solve for a
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