Asked by desai

two towns A and B are 96km apart a is due north of B. town C is 80km from B and is on a bearing of 56 degree from B find distance of town A and C
Answered by Steve
using the law of cosines,

AC^2 = 96^2 + 80^2 - 2*96*80 cos56°
Answered by desai maimbo
AC^2=96^2+80^2-2(96*80)cos56
AC=\/15616-8477.63
AC=9.2km
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