Asked by Anonymous
                At one end of the Venturi Tube the pressure and speed of flowing water is 21 kPa and 0.05m/s respectively.  At another point the pressure is 5 kPa.  Find the speed of the water at the second point.  Answer in m/s
            
            
        Answers
                    Answered by
            bobpursley
            
    p1+1/2 dV1^2=p2+cV2^2  d=densitywater
23k+1/2 *1E3*.0025=5k+1/2*1E3*V2^2
V2^2=(23E3 +500*.0025-5000)/500
= 36
V2=6m/s
check my math.
    
23k+1/2 *1E3*.0025=5k+1/2*1E3*V2^2
V2^2=(23E3 +500*.0025-5000)/500
= 36
V2=6m/s
check my math.
                    Answered by
            Anonymous
            
    The math was right, but 23k should be 2k Pa
    
                    Answered by
            Anonymous
            
    23 should be 21
    
                    Answered by
            Anonymous
            
    So, the answer is 0.0351240737 m/s
    
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