Asked by Anonymous

At one end of the Venturi Tube the pressure and speed of flowing water is 21 kPa and 0.05m/s respectively. At another point the pressure is 5 kPa. Find the speed of the water at the second point. Answer in m/s
Answered by bobpursley
p1+1/2 dV1^2=p2+cV2^2 d=densitywater
23k+1/2 *1E3*.0025=5k+1/2*1E3*V2^2

V2^2=(23E3 +500*.0025-5000)/500
= 36

V2=6m/s

check my math.
Answered by Anonymous
The math was right, but 23k should be 2k Pa
Answered by Anonymous
23 should be 21
Answered by Anonymous
So, the answer is 0.0351240737 m/s