Asked by carina 78

Consider a tube that is 1.0 meter long. If NH3 gas is introduce at the 0-m mark at the same time HCl gas is introduced at the 1-m mark, how far down the tube will the ring of gas occur?
Answered by DrBob222
|---------------------|
0...x.........|..1-x..|<< 1meter

distance NH3 travels = x
distance HCl travels = 1-x
(x/1-x) = sqrt(molar mass HCl/molar mass NH3)
Solve for x and 1-x.
I estimated x = about 60 cm and 1-x about 40 cm.
Answered by carina 78
thank you
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