Ask a New Question

Question

Find the limit of sin4x/(sqrt(x)) as it approaches positive infinity.
16 years ago

Answers

bobpursley
the numerator is bounded between -1 and 1, and the denominator approaches inf.

Looks like zero to me.
16 years ago

Related Questions

limit h->0 [sqrt((4+h)) - 2] / h = ? Thanks multiply numerator and denominator by [sqrt(4+h)+2... Find the limit Limit as h approaches 0 of : SqRt(4+h)-2 ____________ h by rela... find dy/dx of sqrt(x+y)+sqrt(xy)=6 Find the limit limit as x approaches 1 of (2-x)^3tan[(pi/2)x] find the limit of ((sqrt(x+4))-2)/x as x approaches 0. limit (x-9)/(sqrt(x))-3 as x-->9 if f(x) = sin4x-cos2x, find f(pi/8) Limit x approches 1(sqrt(1+2x)-(sqrt3x))/(sqrt(3+x)-2sqrt(x)) Find the limit. (If the limit is infinite, enter '∞' or '-∞', as appropriate. If the limit does not... Sqrt(128/x)=x/sqrt(512)…find x A)14 B)16 C)24 D)18
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use