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Sidney
What is the pH of a 0.05 M solution of acetic acid knowing that it was 2% ionized
Answers
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Answered by
DrBob222
Acetic acid = HAc
.........HAc ==> H^+ + Ac^-
I........0.05....0......0
C........-x......x......x
E......0.05-x...x......x
You know x = 0.05 x 0.02 = ? = (H^+).
Then pH = -log(H^+) = ?
Answered by
Anonymous
2.8
Answered by
Anonymous
2.8
4.1
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